3.365 \(\int \frac {1}{x (1-c^2 x^2)^{5/2} (a+b \sin ^{-1}(c x))} \, dx\)

Optimal. Leaf size=31 \[ \text {Int}\left (\frac {1}{x \left (1-c^2 x^2\right )^{5/2} \left (a+b \sin ^{-1}(c x)\right )},x\right ) \]

[Out]

Unintegrable(1/x/(-c^2*x^2+1)^(5/2)/(a+b*arcsin(c*x)),x)

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Rubi [A]  time = 0.14, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{x \left (1-c^2 x^2\right )^{5/2} \left (a+b \sin ^{-1}(c x)\right )} \, dx \]

Verification is Not applicable to the result.

[In]

Int[1/(x*(1 - c^2*x^2)^(5/2)*(a + b*ArcSin[c*x])),x]

[Out]

Defer[Int][1/(x*(1 - c^2*x^2)^(5/2)*(a + b*ArcSin[c*x])), x]

Rubi steps

\begin {align*} \int \frac {1}{x \left (1-c^2 x^2\right )^{5/2} \left (a+b \sin ^{-1}(c x)\right )} \, dx &=\int \frac {1}{x \left (1-c^2 x^2\right )^{5/2} \left (a+b \sin ^{-1}(c x)\right )} \, dx\\ \end {align*}

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Mathematica [A]  time = 6.34, size = 0, normalized size = 0.00 \[ \int \frac {1}{x \left (1-c^2 x^2\right )^{5/2} \left (a+b \sin ^{-1}(c x)\right )} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[1/(x*(1 - c^2*x^2)^(5/2)*(a + b*ArcSin[c*x])),x]

[Out]

Integrate[1/(x*(1 - c^2*x^2)^(5/2)*(a + b*ArcSin[c*x])), x]

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fricas [A]  time = 2.10, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-\frac {\sqrt {-c^{2} x^{2} + 1}}{a c^{6} x^{7} - 3 \, a c^{4} x^{5} + 3 \, a c^{2} x^{3} - a x + {\left (b c^{6} x^{7} - 3 \, b c^{4} x^{5} + 3 \, b c^{2} x^{3} - b x\right )} \arcsin \left (c x\right )}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(-c^2*x^2+1)^(5/2)/(a+b*arcsin(c*x)),x, algorithm="fricas")

[Out]

integral(-sqrt(-c^2*x^2 + 1)/(a*c^6*x^7 - 3*a*c^4*x^5 + 3*a*c^2*x^3 - a*x + (b*c^6*x^7 - 3*b*c^4*x^5 + 3*b*c^2
*x^3 - b*x)*arcsin(c*x)), x)

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(-c^2*x^2+1)^(5/2)/(a+b*arcsin(c*x)),x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,x):;OUTPUT:sym2
poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

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maple [A]  time = 5.46, size = 0, normalized size = 0.00 \[ \int \frac {1}{x \left (-c^{2} x^{2}+1\right )^{\frac {5}{2}} \left (a +b \arcsin \left (c x \right )\right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x/(-c^2*x^2+1)^(5/2)/(a+b*arcsin(c*x)),x)

[Out]

int(1/x/(-c^2*x^2+1)^(5/2)/(a+b*arcsin(c*x)),x)

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maxima [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (-c^{2} x^{2} + 1\right )}^{\frac {5}{2}} {\left (b \arcsin \left (c x\right ) + a\right )} x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(-c^2*x^2+1)^(5/2)/(a+b*arcsin(c*x)),x, algorithm="maxima")

[Out]

integrate(1/((-c^2*x^2 + 1)^(5/2)*(b*arcsin(c*x) + a)*x), x)

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mupad [A]  time = 0.00, size = -1, normalized size = -0.03 \[ \int \frac {1}{x\,\left (a+b\,\mathrm {asin}\left (c\,x\right )\right )\,{\left (1-c^2\,x^2\right )}^{5/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x*(a + b*asin(c*x))*(1 - c^2*x^2)^(5/2)),x)

[Out]

int(1/(x*(a + b*asin(c*x))*(1 - c^2*x^2)^(5/2)), x)

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sympy [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{x \left (- \left (c x - 1\right ) \left (c x + 1\right )\right )^{\frac {5}{2}} \left (a + b \operatorname {asin}{\left (c x \right )}\right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(-c**2*x**2+1)**(5/2)/(a+b*asin(c*x)),x)

[Out]

Integral(1/(x*(-(c*x - 1)*(c*x + 1))**(5/2)*(a + b*asin(c*x))), x)

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